Prove: sum of a finite dim. subspace with a subspace is closed

In summary, a subspace is considered closed if the sum of any two vectors in the subspace results in another vector in the same subspace. Proving the closure of a finite dimensional subspace with another subspace is important because it demonstrates the fundamental concept of subspace addition and allows for easy identification of subspaces. This can be proven by using the definition of a subspace and showing that the sum of any two vectors in the subspace satisfies the properties of a subspace. This proof can be extended to any number of subspaces as long as they are all finite dimensional. It is crucial for a subspace to be finite dimensional in this proof because it relies on properties such as having a finite basis and being able to represent any
  • #1
CornMuffin
55
5

Homework Statement


Prove:
If ##X## is a (possibly infinite dimensional) locally convex space, ##L \leq X##, ##dimL < \infty ##, and ##M \leq X ## then ##L + M## is closed.

Homework Equations


The Attempt at a Solution



##dimL < \infty \implies L## is closed in ##X##
##L+M = \{ x+y : x\in L, y \in M \} \implies ^{??} dim(L+M) < \infty \implies L+M ## is closed in ##X##

Homework Statement


Homework Equations


The Attempt at a Solution

 
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  • #2
Don't you need M to be closed as well??

Anyway, your attempt isn't correct since L+M doesn't need to be finite-dimensional.
 

1. What does it mean for a subspace to be closed?

For a subspace to be closed, it means that whenever we take the sum of any two vectors in the subspace, the result will also be in the subspace.

2. Why is proving the sum of a finite dimensional subspace with a subspace being closed important?

This proof is important because it shows that the sum of two subspaces is also a subspace, which is a fundamental concept in linear algebra. It also allows us to easily determine if a set of vectors is a subspace or not.

3. How do we prove that the sum of a finite dimensional subspace with a subspace is closed?

To prove this, we can use the definition of a subspace and show that the sum of any two vectors in the subspace satisfies the properties of a subspace, such as closure under addition and scalar multiplication.

4. Can we generalize this proof to any number of subspaces?

Yes, this proof can be generalized to any number of subspaces as long as all the subspaces are finite dimensional. The result will still hold true and the sum of all the subspaces will also be a subspace.

5. Why is it important for a subspace to be finite dimensional in this proof?

The proof relies on the properties of finite dimensional subspaces, such as having a finite basis and being able to represent any vector in the subspace as a linear combination of the basis vectors. These properties are crucial in showing that the sum of a finite dimensional subspace with another subspace is also a subspace.

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