- #1
Marmoteer
- 8
- 0
for example
if [itex]f(x) = \frac{x^{2} - 1}{x+1}[/itex]
they by factoring:
[itex]f(x) = \frac{x^{2} - 1}{x+1}
= \frac{(x + 1)(x - 1)}{x+1}
= x - 1 [/itex]
thus the simplified version is [itex]x - 1[/itex]
let's say [itex]g(x) =[/itex] simplified [itex] f(x)[/itex]
[itex]g(x) = x - 1 [/itex]
meaning [itex]g(x) = f(x)[/itex]
but
[itex]g(-1) ≠ f(-1)[/itex]
am I missing something?
if [itex]f(x) = \frac{x^{2} - 1}{x+1}[/itex]
they by factoring:
[itex]f(x) = \frac{x^{2} - 1}{x+1}
= \frac{(x + 1)(x - 1)}{x+1}
= x - 1 [/itex]
thus the simplified version is [itex]x - 1[/itex]
let's say [itex]g(x) =[/itex] simplified [itex] f(x)[/itex]
[itex]g(x) = x - 1 [/itex]
meaning [itex]g(x) = f(x)[/itex]
but
[itex]g(-1) ≠ f(-1)[/itex]
am I missing something?
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