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Setting Out Arcby tomtomtom1
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#1
Apr2314, 04:42 PM

P: 49

Hello all
I was hoping someone could help me with a geometry problem. Firstly this is not a homework question – this is work related I am just not very good with Maths. I have been asked to set out an arc for a wall. I have been given all the values I need but I do not know how the values were work out. The problem is this: I have an arc with a radius and start coordinates and end coordinates, there are straight lines that are tangent to the arc on either side. If I was standing on the start of the arc and walked 10m in the x axis what would the Y value be to the arc. Hope that makes sense. I have attached a sketch to help get my point across. I really want to know how it is worked out. Thanks 


#2
Apr2314, 05:14 PM

PF Gold
P: 6,121

Problem is indeterminate given that information. The most significant piece of information not provided is what KIND of arc is it? I guess we can assume circular with radius R, but asking people to help solve a problem based on assumptions can be a waste of time. Also, you HAVE to specify at least one of Y1, Y2. Also, is the blue line supposed to be vertical?
You should post your image up and down, not sideways. 


#3
Apr2314, 05:43 PM

P: 49

I see the confusion.
The idea was to find a generic way of getting the results but by stating R=2000 I realize the issue the problem it has caused. So to be specific: The green line is straight and tangent to the arc at coordinates 860,102.800. The arc has a radius of 2000 & is circular. The blue line is straight and tangent to the arc at coordinates 900, 103.202. The points are all in a flat plane and is represented in a standard Cartesian coordinates system. 


#4
Apr2314, 06:12 PM

PF Gold
P: 6,121

Setting Out Arc
So X1 is both 200 and 860 and X2 is both 230 and 900. You have lost me completely.



#5
Apr2314, 06:15 PM

P: 49

X1= 860, y1= 102.800
x2 = 900, y2 = 103.202 


#6
Apr2314, 06:43 PM

PF Gold
P: 6,121




#7
Apr2314, 07:11 PM

P: 49

I have redone the sketch, hopefully this will clear things up



#8
Apr2314, 07:24 PM

PF Gold
P: 6,121

OK, NOW I belive that you have a full problem statement that probably has a solution. I'm hoping, for your sake that there is an easier way than what I have to find the solution, but here's one way:
You have two points (X1,Y1 and X4,Y4) which will give you the slope of the line between them You can easily get the midpoint between the two Now you have a point and the inverse of the slope, which gives you the equation of a line. You have one point on the line and you know that there is another point on the line that is the center of the circle (but you don't know how far away it is) and you know the radius of the circle From that you can construct a rather messy equation for the circle that will have unknowns in it You have two points on the circle and an equation for the circle. The SHOULD, I think, be enough to solve for the unknows, thus giving you the equation of the circle. From there you just plug in the X values and solve for the Y values. Good luck with that. The green and blue lines, by the way, are totally irrelevant and can be erased. They have no bearing on the solution. Also, based on the numbers you gave for X1,Y1 and X2, Y2 (which I assume is not X4,Y4), your drawing is massively out of scale so I'm dubious about this actually being a realworld problem. 


#9
Apr2414, 01:23 PM

HW Helper
Thanks
PF Gold
P: 7,583

Also, are the two straight lines given ahead of time and the curve has to match their slopes or do you make them tangent to the circle after you are done? 


#10
Apr2414, 02:02 PM

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P: 6,121




#11
Apr2414, 02:40 PM

HW Helper
Thanks
PF Gold
P: 7,583




#12
Apr2414, 02:55 PM

HW Helper
Thanks
PF Gold
P: 7,583

@tomtomtom1: Is this a real world construction site problem where you have the two walls specified and need to lay out a chalk line for the arc between them?



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