The point of force application

[The-alexandra]

Homework Statement

Hello everyone
I have got a cylindrical 6 axis force sensor (so I have the force Fx, Fy,Fz and torque Tx, Ty, Tz). Using these data I don’t know how I can find the point of force application.

Homework Equations

The Attempt at a Solution

I try this
The torque can be defined as the cross product I (Position vector) and F(force)
Tx,y,z=Ix,y,z ^Fx,y,z
So, I have 3 equations
Tx=IyFz-IzFy
Ty=IzFx-IxFz
Tz=IxFy-IyFx
But, when I solve the equation(in order to find Ix, Iy and Iz) , the variables in the equation vanish…

Do you have an idea how find this point.
Really thanks so much
Alexandra :shy:

 

[Basic_Physics]

You can get the lever arms from the force and torque values.

 

[The-alexandra]

yes. if you see I try this is in "The attempt at a solution"
but its not possible fin Ix, Iy and Iz

 

[Basic_Physics]

Isn't torque r crossproduct F?

 

[The-alexandra]

yes I call I the Position vector.. in your case r .. the 2 arethe same..

 

[haruspex]

But, when I solve the equation(in order to find Ix, Iy and Iz) , the variables in the equation vanish…

You can't expect it to give a specific vector for I. Suppose a solution is force G acting through the point r. Let s be any vector collinear with G. Then a force G acting through the point r+s is also a solution (indeed, the same solution really).
One way to fix that is to add the equation I.F = 0

 

[The-alexandra]

hi.
if I understand you told me
Ixyz . Fxyz = 0
in order to find a colinear vector. ??

 

[haruspex]

hi.
if I understand you told me
Ixyz . Fxyz = 0
in order to find a colinear vector. ??

No, not in order to find a collinear vector; in order to find a perpendicular one.
Consider a force F acting through some point in an object. You could shift the point of application to anywhere in that same straight line and it would be exactly the same. I.e. a force acts through a line rather than through any specific point of the line. That's why your original equations were not enough to pin down a point.
Now, any I satisfying your equations would be a perfectly good answer. I merely proposed one way of selecting a specific point from that whole line of valid answers, namely, the point that made the I vector orthogonal to the F vector.