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In summary, the conversation discusses the calculation of the moment needed for a scoop to scoop up a sample of sand. The concept of momentum and impulse is brought up, with the suggestion that impulse may be more relevant in this context. More information on the specific sampling task is needed to provide a more accurate answer.
  • #1
ExoP
27
0
Hi,

I was thinking of something: How are one supposed to calculate the moment needed for a scoop to scoop up a sample of e.g. sand? Does the classical p=mv work? Any ideas or comments?
 
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  • #2
It's not clear what you mean by your question; it is clearly in a particular context.
P=mv is the momentum of a mass m with velocity v.
A certain Impulse will be needed to accelerate a mass m to velocity v and Impulse is Force times the time it is applied. A small force takes more time to do the job than a large force. I think you may be referring to Impulse rather than the "moment" (=Momentum) in your post.

If you are, in fact, scooping sand, then the scoop could provide less force over a longer time than for, as an example, a golf club, which may have contact for a small fraction of a second. These are general comments and a more useful answer could be given if there were more detail about the actual sampling job you have in mind.
 

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