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nameVoid
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Homework Statement
Sqrt(x^2+y^2)<=z<=x^2+y^2+z^2
With this problem I run into a few questions
The first of which arises at the statement 1/2<=cos^2a
Here I go about writing
-1/sqrt(2)<=cosa<=1/sqrt(2)
But when dealing with trigs it doesn't make any sense to write 3pi/4<=a<=pi/4
So here I suppose we stop thinking with algebra and think logically saying that 3pi/4<=a<=piand 0<=a<=pi/4
But since z >=0 with take only a between 0 and pi/4
Which all semms a bit off track as if there's should be one to follow algebreically
But anyways this is techinaclly correct by me in any case
Next my question is at the stament cosa<=p
Here I must assume the the surface is only that of the sphere above the cone because well the equation of the cone is not in these terms and a is less than Pi/4 giving the straight line rather than the curve of the cone
Only Here p is never going to equal 0 a never goes past pi/4 so its minimum technicHlly is 1/srt(2) I don't know Wtf the book is writting 0<=p<=cosa for
Homework Equations
The Attempt at a Solution
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