Parallel Plates Capacitors (Conceptual)

In summary, the conversation discusses various aspects of two parallel plate capacitors, including their energy storage, charge, voltage, and electric field. It also states that in parallel capacitors, the voltage at all points is equal. The conversation concludes that the voltage at point B is equal to the voltage at point A.
  • #1
anastasiaw
17
0

Homework Statement


The sketch below is a side view of two capacitors consisting of parallel plates in air. The capacitor plates are equal in area but the plate separation differs as shown. Individual capacitors are specified with two letters, for example RS is a single capacitor. The charge on plate R is represented by QR. The capacitors are charged so that the potential (voltage) at A, VA, initially equals 11 volts. For each of the statements choose the proper response.

http://img524.imageshack.us/img524/2959/plotmr2.png


Homework Equations


U = (1/2)CV^2 = (1/2)QV


The Attempt at a Solution


1) The energy stored in capacitor TU is ... the energy
stored in capacitor RS.
LESS THAN: As the charge separation between two plates
increases, so does the energy stored between them. Since
there is a greater charge separation in the plates R and S,
the energy stored in capacitor RS will be greater.

2) If the plate separation for capacitor RS decreases, the
charge on QT will ... .
decrease?: Distance between R and S decreases, so the
voltage between them also decreases. So the voltage between
T and U increases? That means the charge built up on QT
will decrease.

3) QT is ... QR.
GREATER THAN: Since T is closer to its other plate than
U is, QT will be greater than QU. Less charge separation
means a greater charge will build up on the plate.

4) If the plate separation for capacitor TU decreases, the
energy stored in RS will ... .
increase?: Distance between T and U decreases, voltage
across TU decreases, voltage across RS increases, energy
stored increases?

5) The voltage across capacitor RS is ... that across
capacitor TU.
GREATER THAN: The voltage and the charge separation are
directly proportional, so the greater the charge separation
the greater the voltage.

6) The electric field between plates T and U is ... that
between plates R and S.
GREATER THAN: The distance between the two plates is
inversely proportional to the electric field between them.

7) QR + QS is ... zero.
EQUAL TO: The charges on opposite plates have equal and
opposite charges.
 
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  • #2
So the sum of QR and QS will cancel out
and result in zero charge.

8) The voltage at B is ... the voltage at A.
EQUAL TO: Since the capacitors are connected in parallel,
the voltage at all points will be equal. Therefore, the
voltage at B will be equal to the voltage at A.
 
  • #3
This means that the total charge on these
two plates will cancel out and result in a net charge of zero.
 

1. What is a parallel plate capacitor?

A parallel plate capacitor is a type of electrical component that stores electrical energy in the form of an electric field between two conducting plates. It consists of two parallel plates separated by a non-conducting material called a dielectric. When a voltage is applied across the plates, an electric field is created between them, resulting in the storage of electrical energy.

2. How does a parallel plate capacitor work?

A parallel plate capacitor works by storing electrical energy in the form of an electric field between two parallel plates. When a voltage is applied across the plates, electrons are attracted to one plate and repelled from the other, creating an imbalance of charge. This causes an electric field to form between the plates, which can store energy until the voltage is removed.

3. What factors affect the capacitance of a parallel plate capacitor?

The capacitance of a parallel plate capacitor is affected by three main factors: the surface area of the plates, the distance between the plates, and the type of dielectric material between the plates. Generally, a larger surface area and smaller distance between plates will result in a higher capacitance. The type of dielectric material also plays a role, as some materials have a higher dielectric constant, resulting in a higher capacitance.

4. What is the formula for calculating capacitance in a parallel plate capacitor?

The formula for calculating capacitance in a parallel plate capacitor is C = ε0A/d, where C is the capacitance in farads (F), ε0 is the permittivity of free space (8.85 x 10^-12 F/m), A is the surface area of the plates in square meters (m^2), and d is the distance between the plates in meters (m).

5. How can parallel plate capacitors be used in real-world applications?

Parallel plate capacitors have many practical applications, such as in electronic circuits for storing energy, filtering signals, and as sensors for measuring distance, pressure, or humidity. They are also used in power transmission systems, where they can help improve power factor and increase efficiency. Additionally, parallel plate capacitors are commonly used in energy storage devices, such as batteries and supercapacitors.

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