- #1
mr_coffee
- 1,629
- 1
Hello everyone. The question is:
What capacitance is required to store an energy of 8 kWh at a potential difference of 600 V?
\This seems like a simple problem..our professor hasn't went over this yet but i saw in the book. P = U/t; I also saw; U = 1/2CV^2; So they gave me U right? because P = U/t, so U = 8 kWh, i converted this into 8kWsecond, by doing this:
8kwh x 3600sec = 28800kws; I then used:
C = (2U)/v^2; C = [2*28800]/(600)^2 = .16 which was wrong, i also tried just using 8, and 8/3600, all didn't work.
What capacitance is required to store an energy of 8 kWh at a potential difference of 600 V?
\This seems like a simple problem..our professor hasn't went over this yet but i saw in the book. P = U/t; I also saw; U = 1/2CV^2; So they gave me U right? because P = U/t, so U = 8 kWh, i converted this into 8kWsecond, by doing this:
8kwh x 3600sec = 28800kws; I then used:
C = (2U)/v^2; C = [2*28800]/(600)^2 = .16 which was wrong, i also tried just using 8, and 8/3600, all didn't work.