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jsmith613
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Homework Statement
A laboratory lead consists of 16 strands of fine copper wire twisted together. Each strand is 30 cm long with a diameter of 0.15 mm. Calculate the potential difference across the lead when it is carrying a current of 2.0 A.
(The resistivity of copper = 1.7 × 10^-8 Ohm*m)
Homework Equations
What I would do is R = pl/A and then multiply by 2
BUT I can't find R
The Attempt at a Solution
(the answer is. apparently, 0.036 V but I can't see how)
I said R = [(1.7*10^-8)*16*0.3)/(pi*0.15/20000)^2)