Another Abstract Algebra Question

In summary, the discussion is about determining the order of the group G of symmetries of a cube and whether it maps onto the symmetric group S4 through a group homomorphism. The cube has 24 symmetries and it is unclear how this relates to the group G. The question also asks if the homomorphism is one-to-one and what symmetries are in the kernel of the homomorphism.
  • #1
rocky926
17
0
Another Abstract Algebra Question...

Every symmetry of the cube induces a permutation of the four diagonals connecting the opposite vertices of the cube. This yields a group homomorphism φ from the group G of symmetries of the Cube to S4 (4 is a subscript). Does φ map G onto S4? Is φ 1-1? If not, describe the symmetries in the kernel of φ. Determine the order of G.

So far for this problem I have drawn the cube and the 4 diagonals of the cube. Also I know that the cube has 24 symmetries. I am not sure however how you translate this into a group homomorphism. Does it mean that the group G of symmetries of the Cube contains 24 elements? In which case the order of G would be 24? Thanks for the help!
 
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  • #2
You said that you know that the cube has 24 symmetries. How do you know that? If you do know that, then why ask, "Does it mean that the group G of symmetries of the Cube contains 24 elements"? I ask because I don't know the answer myself, offhand.
 

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