Claw Hammer pulling out a nail

[pegasus24]

Homework Statement

The figure below shows a claw hammer as it is being used to pull a nail out of a horizontal board where θ = 25.1°. A force of 145 N is exerted horizontally as shown. (Assume that the force the hammer exerts on the nail is parallel to the nail.)

(a) Find the force exerted by the hammer claws on the nail.
(b) Find the force exerted by the surface on the point of contact with the hammer head.

Homework Equations

Moment M=Fd

The Attempt at a Solution

The moment at point of contact would be M = 145N * 30cm
I don't know how to proceed from here.. Any help would be appreciated.

 

[Stephen Tashi]

Find the distance from the point of contact to where the hammer grasps the head of the nail. The nail acting on that lever exerts a counterclockwise torque.

 

[pegasus24]

Find the distance from the point of contact to where the hammer grasps the head of the nail. The nail acting on that lever exerts a counterclockwise torque.

Ok I have calculated 1st part:
M=145*0.3
Fcos$$\vartheta$$=M/0.05
=> F=0.96 kN 64.9 degrees above horizontal.

What about the second part?

 

[pegasus24]

Its ok, I figured it out.. Thank you for your hint.. :)

$$\Sigma$$Fx = 0
$$\Sigma$$Fy = 0
Using these equations I got reaction force as 908.75 N.

 

[rwisz]

I would approach this problem by first identifying the key variables and forces at play. In this case, we have a claw hammer pulling a nail out of a horizontal board with a force of 145 N and at an angle of 25.1°. The key forces involved are the force exerted by the hammer on the nail, the force exerted by the surface on the point of contact with the hammer head, and the force of gravity acting on the nail.

To find the force exerted by the hammer claws on the nail, we can use the concept of moments. The moment at the point of contact can be calculated by multiplying the force exerted by the hammer (145 N) by the distance from the point of contact to the force (30 cm). This gives us a moment of 4350 N*cm. Since the force exerted by the hammer claws is perpendicular to the board, we can use the equation M = F*d to solve for the force. Rearranging the equation, we get F = M/d, where M is the moment and d is the distance from the point of contact to the force. Plugging in the values, we get a force of approximately 145 N exerted by the hammer claws on the nail.

To find the force exerted by the surface on the point of contact with the hammer head, we can use the concept of Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, the force exerted by the surface on the hammer head is equal in magnitude but opposite in direction to the force exerted by the hammer on the nail. Therefore, the force exerted by the surface on the point of contact is also approximately 145 N.

In conclusion, the force exerted by the hammer claws on the nail is approximately 145 N, and the force exerted by the surface on the point of contact with the hammer head is also approximately 145 N. These calculations are based on the assumption that the hammer is exerting a horizontal force parallel to the nail, and that there are no other external forces acting on the system. Further experimentation and analysis may be needed to confirm these values.