Specify the reference state for potential energy?

In summary, the potential energy of a spacecraft in circular orbit around the earth is given by the formula E=K+U= 1/2mv2-GmM/r, where r is the distance from the spacecraft to the center of the Earth. The reference state for potential energy is the point at which potential energy is taken to be 0. This can be at the center of the Earth or at infinity, depending on the chosen reference point. However, as r approaches 0, the potential energy becomes undefined or infinite, and thus cannot be exactly 0 at the center of the Earth.
  • #1
charmedbeauty
271
0

Homework Statement



A spacecraft is in circular orbit around the earth. with respect to a point below it on earth, it is traveling towards the east with speed v.

Specify the reference state for potential energy.



Homework Equations





The Attempt at a Solution



the total energy is

E=K+U

= 1/2mv2-GmM/r

but the reference state for potential energy i don't understand?
 
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  • #2
Reference state/level is the one relative to which you measure the potential energy. So in this case it would be _______?
 
  • #3
Infinitum said:
Reference state/level is the one relative to which you measure the potential energy. So in this case it would be _______?

well potential energy is really the distance from the centre of the Earth to the space ship, r in this case.

so the reference level is on Earth which is r- the distance from the spaceship to surface of the earth?
 
  • #4
charmedbeauty said:
well potential energy is really the distance from the centre of the Earth to the space ship, r in this case.

so the reference level is on Earth which is r- the distance from the spaceship to surface of the earth?

Um, no. Let me be more clear. The reference state, in other words, is where the potential energy is taken to be 0. So, where is the potential energy 0?
 
  • #5
Infinitum said:
Um, no. Let me be more clear. The reference state, in other words, is where the potential energy is taken to be 0. So, where is the potential energy 0?

at the centre of the Earth assuming that all the mass in the Earth is evenly distributed.?
 
  • #6
charmedbeauty said:
at the centre of the Earth assuming that all the mass in the Earth is evenly distributed.?

True. The potential is zero there. But are you calculating potential with respect to the center?

The negative of work done against the gravitational force in bringing a mass in, from infinity, to a given point in the gravitational field, is called the gravitational potential energy. Does this give you an idea?
 
  • #7
charmedbeauty said:
at the centre of the Earth assuming that all the mass in the Earth is evenly distributed.?
Not if you're using this formula for PE:
charmedbeauty said:
the total energy is

E=K+U

= 1/2mv2-GmM/r
Using that expression for PE, where is the zero point?
 
  • #8
Doc Al said:
Not if you're using this formula for PE:

Using that expression for PE, where is the zero point?

r→∞

but it's seems strange to me. does that mean that all matter can never have 0 potential energy?
 
  • #9
charmedbeauty said:
r→∞

but it's seems strange to me. does that mean that all matter can never have 0 potential energy?

Yep.

Visibly, as r→∞, the body will have 0 potential energy. But keep in mind that potential energy is defined relative to a reference state, which usually is infinity, and this is crucial to derive the formula that you were using, i.e [itex]-GMm/r.[/itex]

This doesn't stop you from assuming the reference state is the ground level, in which case potential energy at ground is 0, and at a height h, it is [itex]\int F dh[/itex], which for small heights comes out as [itex]mgh[/itex]
 
  • #10
charmedbeauty said:
r→∞
Right. Using that formula implies that you are taking PE = 0 as r → ∞.
but it's seems strange to me. does that mean that all matter can never have 0 potential energy?
The place you choose to call PE = 0 is arbitrary. (But using that formula is very convenient for some purposes.) What physically matters is the change in PE as you go from one point to another, which is independent of the arbitrary PE = 0 reference point.
 
  • #11
Doc Al said:
Right. Using that formula implies that you are taking PE = 0 as r → ∞.

The place you choose to call PE = 0 is arbitrary. (But using that formula is very convenient for some purposes.) What physically matters is the change in PE as you go from one point to another, which is independent of the arbitrary PE = 0 reference point.

ok, but doesn't P.E only →0 since r can only ever→∞

from PE=-GmM/r

PE→0 as r→∞

Since r can never = ∞

how can it be that PE can =0

??
 
  • #12
charmedbeauty said:
ok, but doesn't P.E only →0 since r can only ever→∞

from PE=-GmM/r

PE→0 as r→∞

Since r can never = ∞

how can it be that PE can =0

??
Right. The PE never quite equals zero for finite r. PE goes to zero as r goes to infinity. But it's perfectly OK as a reference point.
 
  • #13
Doc Al said:
Right. The PE never quite equals zero for finite r. PE goes to zero as r goes to infinity. But it's perfectly OK as a reference point.

Ok thanks, but if the Earth is perfectly spherical with the mass evenly distributed, what would be the PE of a particle in the centre of the earth? I thought it should be zero, but are you saying that it does have a discrete amount of PE?
 
  • #14
charmedbeauty said:
Ok thanks, but if the Earth is perfectly spherical with the mass evenly distributed, what would be the PE of a particle in the centre of the earth? I thought it should be zero, but are you saying that it does have a discrete amount of PE?
On what basis would you say that a particle at the center of the Earth would have zero PE? What are you using as your reference point? Just because the gravitational force is zero doesn't mean that the PE is zero.
 
  • #15
Doc Al said:
On what basis would you say that a particle at the center of the Earth would have zero PE? What are you using as your reference point? Just because the gravitational force is zero doesn't mean that the PE is zero.

the centre of the earth. using -GmM/r when r→0 i.e. as a particle gets closer to the centre of the earth. what does this mean its PE→?
is it undefined...or should PE→∞..for a point particle can it not be exactly in the centre of the Earth so that PE≠-GmM/0..ie PE≠∞?
 
  • #16
charmedbeauty said:
the centre of the earth. using -GmM/r when r→0 i.e. as a particle gets closer to the centre of the earth. what does this mean its PE→?
is it undefined...or should PE→∞..for a point particle can it not be exactly in the centre of the Earth so that PE≠-GmM/0..ie PE≠∞?

But the formula (-GMm/r) changes as the particle crosses the ground level, PE will not be infinite. It changes according to a corollary of the shell theorem, which gives that the gravitational force varies linearly from the Earth's surface to its center, and becomes zero at the center. Hence, the potential energy will also vary in accordance to this rule.
 
  • #17
charmedbeauty said:
the centre of the earth. using -GmM/r when r→0 i.e. as a particle gets closer to the centre of the earth. what does this mean its PE→?
is it undefined...or should PE→∞..for a point particle can it not be exactly in the centre of the Earth so that PE≠-GmM/0..ie PE≠∞?
You cannot apply the formula PE = -GmM/r for points within the surface of the earth. Instead, think in general principles: How much work against gravity would be required to raise a particle from the center of the Earth to an arbitrary point?
 
  • #18
Doc Al said:
You cannot apply the formula PE = -GmM/r for points within the surface of the earth. Instead, think in general principles: How much work against gravity would be required to raise a particle from the center of the Earth to an arbitrary point?

Oh right, of course. Thanks Doc al and Infinitum for the explenations.
 

1. What is a reference state for potential energy?

A reference state for potential energy is a specific point of reference used to measure the potential energy of a system. It is typically chosen as the state in which the potential energy is zero, and all other values are relative to this state.

2. Why is a reference state necessary for measuring potential energy?

Without a reference state, potential energy cannot be accurately measured or compared between different systems. It provides a standard point of comparison and allows for the calculation of potential energy differences.

3. How is the reference state determined?

The reference state is usually chosen based on the specific system being studied and the type of potential energy being measured. For example, in gravitational potential energy, the reference state is often chosen as the height at which the object is at rest.

4. Can the reference state change?

Yes, the reference state can change depending on the context and the needs of the scientist. For example, in thermodynamics, the reference state for potential energy may be different for different types of energy (e.g. internal energy, enthalpy).

5. How does the reference state affect potential energy calculations?

The choice of reference state can greatly impact the calculated potential energy of a system. Choosing a different reference state may result in different absolute values of potential energy, but the relative differences between systems will remain the same.

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