Question on heat transfer of a plane wall

[sero2000]

Homework Statement

A plane wall of 152 mm thickness has surface area of 2.32 m2. One side of the wall is kept at 82.2 oC, and the other side at 4.4 oC. The thermal conductivity of the wall material is 0.036 W/m.K at 0 oC, and that at 93.3 oC is 0.055 W/m.K. Calculate the rate of heat conduction through the wall

Homework Equations

Q= ∆T/R

The Attempt at a Solution

I do understand how to do this but i gt stuck at the part of the question that says "The thermal conductivity of the wall material is 0.036 W/m.K at 0 oC, and that at 93.3 oC is 0.055 W/m.K"

Anyone can just explain to me what does it mean?

 

[djeitnstine]

That means you should estimate the thermal conductivity at your required temperatures

 

[nlightner]

The thermal conductivity of a material refers to its ability to conduct heat. It is a measure of how easily heat can pass through the material. In this question, the thermal conductivity of the wall material is given as 0.036 W/m.K at 0 oC, which means that at a temperature of 0 oC, the material has a thermal conductivity of 0.036 W/m.K. Similarly, at a temperature of 93.3 oC, the thermal conductivity of the material is 0.055 W/m.K. This indicates that the thermal conductivity of the material increases as the temperature increases. This is important to consider when calculating the rate of heat conduction through the wall, as the temperature difference between the two sides of the wall will affect the rate of heat transfer.