- #1
Qyzren
- 44
- 0
The neutrino flux from supernova 1987A was estimated to be 1.3e14 m^-2 at the Earth. SN 1987A occurred in the Large Magellanic cloud, which is located at a distance of 50 kpc. If the average energy per neutrino was 4.2 MeV, estimate the amount of energy released in the form of neutrinos during the supernova explosion
electron volt = 1.602e-19 J
pc = 3.086e16 m
Answer says: 2.6e45 J
I can't seem to get the answer... :(
any help will be appreciated :)
i was thinking since flux falls off ~ 1/d².
so i tried E = flux *d²*avg energy of neutrino
1.3e14*(50000*3.086e16)²*4.2e6*1.602e-19
=3.258e44 J.
So I'm off by more than a factor of 10... :(
What am i doing wrong??
Homework Equations
electron volt = 1.602e-19 J
pc = 3.086e16 m
The Attempt at a Solution
Answer says: 2.6e45 J
I can't seem to get the answer... :(
any help will be appreciated :)
i was thinking since flux falls off ~ 1/d².
so i tried E = flux *d²*avg energy of neutrino
1.3e14*(50000*3.086e16)²*4.2e6*1.602e-19
=3.258e44 J.
So I'm off by more than a factor of 10... :(
What am i doing wrong??