- #1
Qyzren
- 44
- 0
Two identical, oppositely-charged, conducting plates of area 2.50cm² are separated by a dielectric 1.80 mm thick, with a dielectric constant of 3.60. The resultant electric field in the dielectric is 1.2*10^6 V/m.
a)Compute the charge per unit area on the conducting plate.
b)Compute the charge per unit area on the surfaces of the dielectric.
for part a). I used gauss's law for dielectric.
Q/A = K*epsilon_0*E = 3.60*8.85*10^-12*1.2*10^6 = 3.82*10^-5 C/m² which is correct.
However i haven't got a single clue how to do part b. But the answer is suppose to be 2.76*10^-5 C/m². Can someone please help me figure out how this answer was obtained?
a)Compute the charge per unit area on the conducting plate.
b)Compute the charge per unit area on the surfaces of the dielectric.
The Attempt at a Solution
for part a). I used gauss's law for dielectric.
Q/A = K*epsilon_0*E = 3.60*8.85*10^-12*1.2*10^6 = 3.82*10^-5 C/m² which is correct.
However i haven't got a single clue how to do part b. But the answer is suppose to be 2.76*10^-5 C/m². Can someone please help me figure out how this answer was obtained?