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giacomh
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Homework Statement
Water enters a kidney through a tube at 10 mL/min. It exits through a 6-mm-diameter tube at 20 mm/s.What is the rate of change of mass of water in the kidney?
Homework Equations
m=vpa
q=va
After conversions to meters
V=.02
Q=.000167
A=(pi/4)*.006^2 = .0000282
The Attempt at a Solution
dm/dt-Qp+VAp=0
dm/dt-(.000167)(999.1)+(.0000282)(.02)(999.1)=0
dm/dt=.165 kg/s
Needless to say, that's not the right answer, but I can't figure out where I went wrong.