- #1
Juntao
- 45
- 0
Here's what I got to prove where '.' is dot.
A.B=A.C Then B=C True or false? If true, prove it in general terms, if false, provide a counter-example.
Ok, I just need some body to comment on my little proof here, and any guidelines to make it more thorough or whatnot.
I know that the dot product is commutative,
A.(B+C)=A.B +A.C, but not sure if it really needs to be in my proof or not.
Proof
------
Say A.B=N and A.C=N (where N is a scalar number)
so if N=N
Then A.B=A.C
If I cancel the A's, I get B=C.
Is that a good way to approach that, or is there a better way of expressing it?
A.B=A.C Then B=C True or false? If true, prove it in general terms, if false, provide a counter-example.
Ok, I just need some body to comment on my little proof here, and any guidelines to make it more thorough or whatnot.
I know that the dot product is commutative,
A.(B+C)=A.B +A.C, but not sure if it really needs to be in my proof or not.
Proof
------
Say A.B=N and A.C=N (where N is a scalar number)
so if N=N
Then A.B=A.C
If I cancel the A's, I get B=C.
Is that a good way to approach that, or is there a better way of expressing it?