- #1
Tido611
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ok i need a little bit of help understanding this, I've read over it ten times and it still is making no sense to me
"a given network, with constant voltages and resistance produces a current flow in the load resistor equal to that which flows if the load resistor were applied across an equivalent circuit which has a) an internal resistnace measured at the terminals of the circiut with the voltage source replaced by its equivalent internal resistance; b)a vltage at the termainlas equal to that existing in the original circiut after removal of the load resistor"
like i said I've read it ten times and I am still pulling nothing from it so if anyone could explain this in simpler terms it would be greatly appreciated.
"a given network, with constant voltages and resistance produces a current flow in the load resistor equal to that which flows if the load resistor were applied across an equivalent circuit which has a) an internal resistnace measured at the terminals of the circiut with the voltage source replaced by its equivalent internal resistance; b)a vltage at the termainlas equal to that existing in the original circiut after removal of the load resistor"
like i said I've read it ten times and I am still pulling nothing from it so if anyone could explain this in simpler terms it would be greatly appreciated.