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Embarrassing electronics problem (logic gates) |
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| Feb4-13, 07:03 AM | #18 |
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Embarrassing electronics problem (logic gates)Because it looks like you are experiencing problems with basic circuit theory, not diodes. In logic gates like the one you've shown here, diodes and transistors are nothing more than controlled switches. Transistors can act as closed or open switches by providing a suitable base or gate voltage. Diodes can act as closed or open switches by providing a suitable voltage at the 'gate input' terminal (if Vanode>Vcathode then it's a closed switch, otherwise it's open). Once you understood how the gate works with ideal devices, you can refine your analysis by considering the effects of real devices (like diode drop voltage, internal resistances, parasitic capacitances...). |
| Feb5-13, 10:58 PM | #19 |
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wannab, think of diodes as one-way valves. if the applied voltage is positive (or exceeds about 0.6 v), it conducts and if the applied voltage is negative, it does not conduct.
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| Feb6-13, 04:13 AM | #20 |
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If you have started or completed any Physics or Electronics course then you should have or will have the knowledge. Otherwise, you will need to do a bit of self-education. There is no easy way to 'get' Electronics. Some people approach it by building and testing circuits on their own. That can work but you can't beat being taught the basics first. There is no point in saying that you just don't like diodes. You can't be selective in this way. The expression "blocking the current" means very little, in the wrong context. |
| Feb6-13, 03:40 PM | #21 |
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| Feb6-13, 04:01 PM | #22 |
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OK then. What's the problem with diodes, which go low resistance when forward biased and high resistance when reverse biased? That's all you need to remember when you look at the diode logic circuit. You can't let diodes spoil your day. Have another go.
Are you doing a course at the moment? |
| Feb6-13, 04:51 PM | #23 |
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| Feb6-13, 05:07 PM | #24 |
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As you say, the leakage current for a diode is fractions of a microAmp and for transistor circuits the leakage could be higher. But is this relevant, when all a logic gate needs to detect is whether an input is near one or the other discrete levels? What do you think that tiny reverse current can do to effect the operation of the circuit? It has 'no significant' effect at all.
In the Diode version of an OR gate, if one input OR the other OR both are held at a 'low' voltage, then current will flow through the common resistor (at the top) and the output voltage will be low (a logic 0). This output level (0.6V) will be low enough to act as a 'zero' input for a subsequent gate. This process can only be taken so far, because each gate will have an output voltage value which is 0.6V higher than the previous one. The 0.6Vs will add up, eventually the resulting ('0') voltage output will be almost at the input supply level . This is where a transistor (active) gate works better because the logic levels are maintained/ regenerated from gate to gate. |
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| diodes, electronics, gate, logic, misunderstanding |
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