- #1
engineer2010
- 10
- 0
Homework Statement
What mass of steam at 100 Celcius must be added to 1.00 kg of ice at 0 Celcius to yield liquid water at 20 Celcius.
Homework Equations
Q = mL
Q = mc(deltaT)
change in energy = 0
The Attempt at a Solution
Ice
m= 1.00
c = 2100
T1 = 0
Tf =
L = 333
water
m=
c = 4190
T1 =
Tf= 20
Steam
m = ?
c = 2010
L = 2260
T1 = 100
Tf =
I am stil missing some of the needed information and i am not sure how to organize my equations.