- #1
geoduck
- 258
- 2
Consider the S-matrix:
<f|U(t,-t)|i>
When going into the interaction picture, this becomes:
[tex]<f_I|U_I(t,-t)|i_I> [/tex]
where the propagator is the interaction picture propagator, and the states are interaction states.
Can you say that:
[tex]<f_I|U_I(t,-t)|i_I>= <f|U_I(t,-t)|i>[/tex] ?
It seems that the two sides of the above equation differ by phase factors that don't really matter when calculating probabilities.
However, when making calculations, don't the states |i> and |f> need to be in the Schrodinger picture?
<f|U(t,-t)|i>
When going into the interaction picture, this becomes:
[tex]<f_I|U_I(t,-t)|i_I> [/tex]
where the propagator is the interaction picture propagator, and the states are interaction states.
Can you say that:
[tex]<f_I|U_I(t,-t)|i_I>= <f|U_I(t,-t)|i>[/tex] ?
It seems that the two sides of the above equation differ by phase factors that don't really matter when calculating probabilities.
However, when making calculations, don't the states |i> and |f> need to be in the Schrodinger picture?