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Formula for missing person's weight from team of 5

by 20GT
Tags: formula, missing, person, team, weight
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mfb
#19
Jul19-14, 02:50 PM
Mentor
P: 11,602
@20GT: They could assume that the weight of X at the start is the same as the average of the others, then
(summed weight loss) = 4/5 * (starting weight of 5) - (final weight of 4)

I don't see reasonable other assumptions.


@disregardthat: I don't think it is reasonable. If X is heavier than average, you get a lot of imaginary weight loss (formula gives a large result without actual weight loss of anyone).
disregardthat
#20
Jul20-14, 08:53 AM
Sci Advisor
P: 1,742
It is more likely he he closer to the average of his group than the average of everyone since he participated in his groups initial weigh in.
mfb
#21
Jul20-14, 11:29 AM
Mentor
P: 11,602
That makes it 20% less bad (as 20% of the weight* in the average comes from him), but still problematic.

*the mathematical weight, not the one in kg.
20GT
#22
Jul21-14, 03:04 AM
P: 10
Thanks everyone
20GT
#23
Jul21-14, 03:08 AM
P: 10
He was taller and fatter than the rest.
2 normal looking weights
1 short fat person
1 short stocky person


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