- #1
zeshkani
- 29
- 0
hi there i have a question in which i can't get the answer i will show my work on what i did, if anybody can help , that would help a lot .
here is the question:
only two forces act on an object (mass= 3kg)
x=40N
a=60N is at 45 degrees above the horizon
y= ?
find the magnitude and direction (relative to the x-axis) of the acceleration of the object?
i can use (a=60N)sin(45)= 42.42degrees, but where do i go from here, or what's the next step, i did try squaring y+x under the square root, but that's not the magnitude, because the answer in teh back of the book is different.
any help is welcome thanks
here is the question:
only two forces act on an object (mass= 3kg)
x=40N
a=60N is at 45 degrees above the horizon
y= ?
find the magnitude and direction (relative to the x-axis) of the acceleration of the object?
i can use (a=60N)sin(45)= 42.42degrees, but where do i go from here, or what's the next step, i did try squaring y+x under the square root, but that's not the magnitude, because the answer in teh back of the book is different.
any help is welcome thanks