- #1
zmike
- 139
- 0
In the Chi-square test, my textbook says that degrees of freedom are the number of independent variables minus one so df = n - 1
does this mean that that n is equal to the number of observed values from the equation aka the number of times I've added together the numbers?
sum [(O-E)^2]/E
Is there an instance where it isn't equal to the number of observed values I have?
(there's an example in my book (but no answer) with an experiment with observed values of 2 trials of genetic crosses where observed in
trial 1 was 0.5
trial 2 was 0.3
but both of these values were measuring the same variable which was heterozygosity. The expected value is 0.8. Does this mean the df = 1? or is it 0 since there is only 1 independent variable?)
thanks!
does this mean that that n is equal to the number of observed values from the equation aka the number of times I've added together the numbers?
sum [(O-E)^2]/E
Is there an instance where it isn't equal to the number of observed values I have?
(there's an example in my book (but no answer) with an experiment with observed values of 2 trials of genetic crosses where observed in
trial 1 was 0.5
trial 2 was 0.3
but both of these values were measuring the same variable which was heterozygosity. The expected value is 0.8. Does this mean the df = 1? or is it 0 since there is only 1 independent variable?)
thanks!