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Degrees of freedom |
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| Feb8-13, 03:43 AM | #1 |
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Degrees of freedom
What are the number of degrees of freedom of
1)a square sheet moving in XY plane 2)a triangular lamina moving freely in XY plane |
| Feb8-13, 01:26 PM | #2 |
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This looks like homework: What did you find out so far?
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| Feb10-13, 02:48 PM | #3 |
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A square is composed of many particles with the constraint that distance between every particle is the fixed.so such a square is moving in XY plane.
if i consider two particles they have 4-1 =3degree of freedom(one is subtracted due to constraint that distance between particles are fixed).if i consider third particle it is defined by two co-ordinates and two constraints and therefore no degree of freedom.....the same for fourth fifth and so on..... so my answer is three and i dont find any difference in this respect with a triangular lamina...... I do not know the answer to the question.......please comment on this and say if you have any other opinion. |
| Feb10-13, 03:38 PM | #4 |
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Degrees of freedom
Those 3 degrees of freedom just fix the current position of the square. What about its movement?
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| Feb10-13, 03:45 PM | #5 |
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if i get generalized co-ordinates i can calculate co-ordinate velocities from it
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| Feb10-13, 03:46 PM | #6 |
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Is that related to the original question?
What do you mean with "get"? |
| Feb10-13, 04:12 PM | #7 |
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The question does not ask that .But i told a general principle.For example a simple pendulum which is oscillating in a plane.since its moving along the arc of a circle(distance from orgin is fixed) it has only one degree of freedom....theta.....which is the angle dat the string makes with vertical.......so if i know theta as a function of time.....i can differentiate "theta" to find generalised co-ordinate velocity
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