
#1
Oct1013, 08:17 AM

P: 2

Can someone provide me with a general understanding of the steps involved in completing this problem. How do I get started?
Calorimetric data on triethylamine (EA)benzene (B) solutions at 298.15 K were obtained and follow the following expression: Hmix [xBHB + (1  xB)HEA] = xB(1  xB)[1418  482.4(1  2xB) + 187.4(1 2xB)3] (a)Develop expressions for (HB  HB) and (HEA  HEA). Note that Hi is the partial molar enthalpy of a species. (b)Compute values for (HB  HB) and (HEA  HEA) at xB = 0.5. (c) One mole of a 25 mol% benzene mixture is to be mixed with one mole of a 75 mol% benzene mixture at 298.15 K. How much heat must be added or removed from the process to be isothermal? 


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