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neoking77
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A cylindrical bucket, open at the top has height 27.0 cm and diameter 13.0 cm. A circular hole with a cross-sectional area 1.49 cm^2 is cut in the center of the bottom of the bucket. Water flows into the bucket from a tube above it at the rate of 2.28×10−4 m^3/s
my work
let 1 denote the top and 2 denote the bottom
Q = V1A1
V1 = Q/A = 0.01718 m/s
Q = V2A2
V2 = 0.01530 m/s
using bernoulli's
top bottom
P + pgh + 1/2pv^2 = pgh + 1/2pv^2 + P
P's are equal and cancels out
rho's cancel out
there's no pgh on bottom
we are left with
h = [ 1/2(v2)^2-1/2(v1)^2 ] /g
the answer i get is 0.00179m which is 0.1179 cm but that's not the answer...can anyone see where i went wrong? thank you very much.
my work
let 1 denote the top and 2 denote the bottom
Q = V1A1
V1 = Q/A = 0.01718 m/s
Q = V2A2
V2 = 0.01530 m/s
using bernoulli's
top bottom
P + pgh + 1/2pv^2 = pgh + 1/2pv^2 + P
P's are equal and cancels out
rho's cancel out
there's no pgh on bottom
we are left with
h = [ 1/2(v2)^2-1/2(v1)^2 ] /g
the answer i get is 0.00179m which is 0.1179 cm but that's not the answer...can anyone see where i went wrong? thank you very much.