- #1
UrbanXrisis
- 1,196
- 1
Question states:
The acceleration of a marble in a certain fluid is proportional to the speed of the marble squared and is given (in SI units) by a=-3.00v^2 for v>0. If the marble enters this fluid with a speed of 1.50m/s, how long will it take before the marble's speed is reduced to half of its initial value?
Here's what I think is it...take the derivative of a... a`=6v
d=6(.75m/s)
d=4.5m
I need the acceleration to sub in for the equation vf = vi + at
to find the time.
Am I doing any of this correct?
The acceleration of a marble in a certain fluid is proportional to the speed of the marble squared and is given (in SI units) by a=-3.00v^2 for v>0. If the marble enters this fluid with a speed of 1.50m/s, how long will it take before the marble's speed is reduced to half of its initial value?
Here's what I think is it...take the derivative of a... a`=6v
d=6(.75m/s)
d=4.5m
I need the acceleration to sub in for the equation vf = vi + at
to find the time.
Am I doing any of this correct?