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gokugreene
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Hey guys could you tell me if I got the right answer; my teacher hasn't went over this material and it is due tomorrow.
Given the following reaction, how many grams of Zn are required to obtain 2.00g of Au?
[tex]4CN^{-1}~+~3Zn~+~2Au(CN)_4^{-1}~~-->~3Zn(CN)_4^{-2}~+~2Au[/tex]
(2.00g of Au)(1 mole Au/179.0g of Au)(3 mole Zn/2 mole Au)(65.39g Zn/1 mole Zn) = 1.10g of Zn
Is this the proper way and is my answer correct? Thanks
Given the following reaction, how many grams of Zn are required to obtain 2.00g of Au?
[tex]4CN^{-1}~+~3Zn~+~2Au(CN)_4^{-1}~~-->~3Zn(CN)_4^{-2}~+~2Au[/tex]
(2.00g of Au)(1 mole Au/179.0g of Au)(3 mole Zn/2 mole Au)(65.39g Zn/1 mole Zn) = 1.10g of Zn
Is this the proper way and is my answer correct? Thanks