- #1
kevinnn
- 119
- 0
My lab group and I are a bit confused. We are doing a lab where we need to calculate the Ksp of calcium hydroxide in pure water and then in different concentrations of calcium chloride and potassium chloride to analyze the diverse and common ion effect. I was absent one day but my lab partner told me that the teacher said Ksp for calcium hydroxide will remain constant for the solutions of potassium chloride and calcium chloride. She wants us to make a graph where we compare the molar solubilities of the different solutions, not the Ksp. My question is how on Earth can something that tells us about solubility, Ksp, remain constant when more is forced to dissolve, KCl, and less is forced to dissolve, CaCl2? Does this mean the molar solubility calculation is really as easy as just determining the calcium ion concentration in each solution and dividing it by the total volume? Gracias!