particles and antiparticles in compex field

by spookyfish
Tags: antiparticle, antiparticles, compex, field, particle, particles
 P: 28 Hi. I am confused about something related to the creation of particles/antiparticles in a complex scalar field. I read in the literature that $\phi(x)|0\rangle$ describes the creation of a particle at point $x$. But given that $$\phi(x) = \int \frac{d^3 p}{\sqrt{(2\pi)^3 2E_p}} \left(a(p)e^{-ipx}+b^\dagger (p)e^{ipx}\right)$$ then in $\phi(x)|0\rangle$ only the $b^\dagger(p)$ term contributes, i.e. $$\phi(x)|0\rangle= \int \frac{d^3 p}{\sqrt{(2\pi)^3 2E_p}}e^{ipx} b^\dagger(p)|0\rangle$$ from which it seems that an anti-particle (created by $b^\dagger(p)$) is created at $x$.
 Sci Advisor HW Helper PF Gold P: 2,606 We don't have the original text that you read around to nitpick, but if ##\phi(x)## creates the antiparticle, then ##\phi^\dagger(x)## creates the particle. The original reference could have been 1. sloppy 2. using a different definition of particle vs antiparticle 3. referring to a real scalar field etc. We simply can't be sure without knowing precisely what you read and the context in which the author stated that.
 P: 28 Thanks. In fact, my problem was with something I read in the internet related to the literature, and I think it was simply wrong, so the definitions I wrote above work.

 Related Discussions High Energy, Nuclear, Particle Physics 10 General Physics 7 Quantum Physics 0 Quantum Physics 19 High Energy, Nuclear, Particle Physics 8