- #1
Mozart
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I don't remember how to do this x^(2/3)=4 solve for x Do you use logarithm or something?
Mozart said:After reading what you said I did the following.
wrote x^2 with the third root around it and made it equal 4.
I then took the square root of 4 to get rid of the square sign on x
I then cubed the 2 and got 8
After pugging the 8 into x^(2/3) I got 4
Please tell me I got the answer using a proper method and this isn't a cruel coincidence. Thanks by the way for the help!
The first step is to take the logarithm of both sides of the equation. This will help us eliminate the exponent and solve for x.
Logarithms allow us to move the exponent from the left side of the equation to the right side, creating a simpler equation to solve.
Since the base of the exponent is not specified, we can use any logarithm. However, it is most common to use the natural logarithm, ln, or the common logarithm, log, in these types of equations.
Next, we use the properties of logarithms to simplify the equation. We can bring down the exponent as a coefficient and then solve for x using basic algebraic techniques.
Yes, since the exponent is 2/3, we must remember to check for extraneous solutions. This means that we must make sure the solutions we obtain from solving the equation actually work when substituted back into the original equation.