What Are the Steps and Considerations for Titration of Vinegar?

  • Thread starter Quincy
  • Start date
  • Tags
    Titration
In summary, a solution of household vinegar is analyzed by using a pipet to measure out 10.0 mL, which is then placed in a 250 mL volumetric flask and diluted with distilled water. A 25.0 mL portion of the diluted solution is then titrated with a standard solution of sodium hydroxide, with a neutralization reaction of HC2H3O2 (aq) + OH- (aq) --> C2H3O2- (aq) + H2O (l). From this, the molarity of the diluted vinegar is calculated to be 0.0334 M, and the molarity of the household vinegar is found to be 0.835 M. Additionally, using the
  • #1
Quincy
228
0

Homework Statement


A solution of household vinegar (a mixture of acetic acid and water) is to be analyzed. A pipet is used to measure out 10.0 mL of the vinegar, which is placed in a 250 mL volumetricflask. Distilled water is added until the total volume of solution is 250 mL. A 25.0 nL portion of the diluted solution is measured out with a pipet and titrated with a standard solution of sodium hydroxide.

The neutralization reaction is as follows:

HC2H3O2 (aq) + OH- (aq) --> C2H3O2- (aq) + H2O (l)

1) It is found that 16.7 mL of 0.0500 M NaOH is needed to titrate 25.0 mL of the diluted vinegar. Calculate the molarity of the diluted vinegar.
.0167 L NaOH x .0500 mol NaOH / 1 L NaOH = 8.35 x 10-4 mol NaOH

8.35 x 10-4 mol NaOH x 1 mol HC2H3O2 / 1 mol NaOH = 8.35 x 10-4 mol HC2H3O2


8.35 x 10-4 mol HC2H3O2 / .0250 L = 0.0334 M HC2H3O2

2) Calculate the molarity of the household vinegar.

250 / 25 = 10

8.35 x 10-4 mol HC2H3O2 x 10 = 8.35 x 10-3 mol HC2H3O2

8.35 x 10-3 mol HC2H3O2 / .0100 L =
0.835 M HC2H3O2

3) The household vinegar has a density of 1.05 g/mL. Calculate the percent by mass of acetic acid in the household vinegar.

1.05 g/mL x 10 mL = 10.5 g HC2H3O2 + H2O

8.35 x 10-3 mol HC2H3O2 x 60.04 g/mol =
0.501 g HC2H3O2

(0.501 g HC2H3O2/ 10.5 g) x 100 = 4.77% HC2H3O2
 
Last edited:
Physics news on Phys.org
  • #2
Looks OK to me.
 
  • #3


I would like to point out a few things about this titration experiment. Firstly, it is important to use accurate and precise measuring tools, such as a pipet and a volumetric flask, to ensure that the results are reliable. Secondly, it is crucial to perform multiple trials to obtain an average value and to check for consistency in the results. This will help to reduce any errors and increase the accuracy of the final measurement. Additionally, it is important to properly label all solutions and to keep track of the units and conversions used in the calculations. Finally, it is also important to be aware of any potential sources of error, such as impurities in the solutions or incorrect measurements, and to take steps to minimize their impact on the results. Overall, this experiment provides a valuable opportunity to practice important laboratory skills and to understand the principles of titration and acid-base reactions.
 

1. What is the purpose of titrating vinegar?

The purpose of titrating vinegar is to determine the exact concentration of acetic acid in the vinegar sample.

2. How is the titration process carried out?

The titration process involves adding a known concentration of a base (such as sodium hydroxide) to a known volume of vinegar until the reaction reaches its endpoint. This can be determined by using an indicator or by monitoring the pH level.

3. Why is it important to perform multiple trials during titration?

Performing multiple trials during titration helps to ensure the accuracy and precision of the results. It allows for any errors or inconsistencies to be identified and corrected.

4. What are the calculations involved in titration?

The calculations involved in titration include determining the amount of base used to reach the endpoint, as well as using the volume and concentration of the base to calculate the concentration of acetic acid in the vinegar sample.

5. What are some sources of error in titration of vinegar?

Some sources of error in titration of vinegar include incorrect measurements of the base or vinegar, not reaching the endpoint accurately, and variations in the concentration of the base solution.

Similar threads

  • Biology and Chemistry Homework Help
Replies
1
Views
1K
  • Biology and Chemistry Homework Help
Replies
5
Views
2K
  • Biology and Chemistry Homework Help
Replies
7
Views
4K
  • Biology and Chemistry Homework Help
Replies
1
Views
3K
  • Biology and Chemistry Homework Help
Replies
2
Views
4K
  • Biology and Chemistry Homework Help
Replies
1
Views
2K
  • Biology and Chemistry Homework Help
Replies
4
Views
3K
  • Biology and Chemistry Homework Help
Replies
7
Views
2K
  • Biology and Chemistry Homework Help
Replies
2
Views
8K
  • Biology and Chemistry Homework Help
Replies
1
Views
9K
Back
Top