you mean 78 N/mm^2John78 said:Homework Statement
A mild steel column has a cross section of 100m by 50mm. Assuming a safety factor of 6 calculate the load that it can safely support
Homework Equations
W=A*δ
The Attempt at a Solution
δ=470 N/mm2*0,1667= 78,34 mm2
about 400 kN, yes, assuming a short column and a FS of 6 against what appears to be an ultimate stress of a mild steel.A=100mm*50mm=5000mm2
W =5000* 78,34=391700/1000=391,7 N??
The formula for calculating the load of a mild steel column is Load = Cross-sectional area x Allowable stress. The cross-sectional area can be determined by multiplying the length of the column by its width and the allowable stress can be found in engineering handbooks or building codes.
To determine the cross-sectional area of a mild steel column, measure the length and width of the column in either inches or millimeters. Then, multiply the length by the width to get the cross-sectional area in square inches or square millimeters.
The allowable stress for a mild steel column depends on the material and its intended use. It can be found in engineering handbooks or building codes. Generally, the allowable stress ranges from 30,000 to 60,000 pounds per square inch (psi) or 210 to 415 megapascals (MPa).
To convert from psi to MPa, multiply the psi value by 0.006895. For example, if the allowable stress for a mild steel column is 45,000 psi, the equivalent in MPa would be 310.275 MPa (45,000 x 0.006895).
No, the formula for calculating the load of a mild steel column is specific to mild steel. Different materials have different properties and require different formulas for calculating load. It is important to use the appropriate formula for the material being used.