- #1
IB1
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Hello everyone, I'm new here, sorry if I make mistakes. My english is poor.
Prove that :
[tex] T=2\pi \sqrt{\frac{l}{g}} [/tex]
where [tex]l[/tex] is length and [tex]g[/tex] is gravity
I hope you understand my question, else: I will try to write it again.
Thank you !
Prove that :
[tex] T=2\pi \sqrt{\frac{l}{g}} [/tex]
where [tex]l[/tex] is length and [tex]g[/tex] is gravity
I hope you understand my question, else: I will try to write it again.
Thank you !