- #1
Izzhov
- 121
- 0
It is possible to put almost every unit in physics in terms of a product of integer powers of mass (kg), displacement/distance (m), time (s), and charge (q). Here are some examples:
[tex] \begin{array}{c} speed = m^1 \times s^{-1} \\ acceleration = m^1 \times s^{-2} \\ jerk = m^1 \times s^{-3} \ \\ momentum = kg^1 \times m^1 \times s^{-1} \\ force = kg^1 \times m^1 \times s^{-2} \\ energy = kg^1 \times m^2 \times s^{-2} \\ power = kg^1 \times m^2 \times s^{-3} \\ pressure = kg^1 \times m^{-1} \times s^{-2} \\ current = q^1 \times s^{-1} \\ voltage = kg^1 \times m^2 \times q^{-1} \times s^{-2} \\ resistance = kg^1 \times m^2 \times q^{-2} \times s^{-1} \end{array} [/tex]
...and so on. My question is: Is there any way to put units of temperature (degrees) into this format?
[tex] \begin{array}{c} speed = m^1 \times s^{-1} \\ acceleration = m^1 \times s^{-2} \\ jerk = m^1 \times s^{-3} \ \\ momentum = kg^1 \times m^1 \times s^{-1} \\ force = kg^1 \times m^1 \times s^{-2} \\ energy = kg^1 \times m^2 \times s^{-2} \\ power = kg^1 \times m^2 \times s^{-3} \\ pressure = kg^1 \times m^{-1} \times s^{-2} \\ current = q^1 \times s^{-1} \\ voltage = kg^1 \times m^2 \times q^{-1} \times s^{-2} \\ resistance = kg^1 \times m^2 \times q^{-2} \times s^{-1} \end{array} [/tex]
...and so on. My question is: Is there any way to put units of temperature (degrees) into this format?
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