Proving Divisibility of n by 6: A Simple Guide

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In summary: So in summary, if n is a natural number and n^2 is divisible by 6, then n is divisible by 6. This can be proven by writing n in terms of its prime factors and showing that if n^2 is divisible by 6, then n must also be divisible by 6. This can also be shown by using the theorem that if p divides ab, then p divides a or p divides b, and applying it to the case of 6 dividing n^2. Therefore, n must be divisible by both 2 and 3, hence by 6.
  • #1
ToastMonger
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I need to prove that if n is a natural number and n^2 is divisible by 6, then n is divisible by 6.

I know that I knew how to do this at one point fairly recently, if you could refresh my memory I would greatly appreciate it.
 
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  • #2
Write n out in terms of it's prime factors, and it should be obvious.
 
  • #3
Suppose n was not divisible by 2. Then n^2 could not be divisible by 6.
Suppose n was not divisible by 3. Then n^2 could not be divisible by 6.
So n is divisible by 2 and 3, hence by 6.
 
  • #4
we know that if p divides ab, then p divides a or p divides b.
now if 6 divides n.n, then 6 divides n.
 
  • #5
Here's another way to look at it.

n(n+1)(2n+1)/6 is the sum of the first n squares, and thus must be an integer. Its numerator is 2n^3 + 3n^2 + n. So if n^2 is divisible by 6, n must be as well.
 
  • #6
we know that if p divides ab, then p divides a or p divides b.
now if 6 divides n.n, then 6 divides n.
6 isn't a prime number, so we cannot apply that theorem directly...
 
  • #7
Why are folks writing up complete solutions to what appears to be a textbook problem?
 
  • #8
Hurkyl said:
murshid_islam said:
we know that if p divides ab, then p divides a or p divides b.
now if 6 divides n.n, then 6 divides n.
6 isn't a prime number, so we cannot apply that theorem directly...
now if 6 divides n.n, then 3 divides n.n and 3 divides n.
again, if 6 divides n.n, then 2 divides n.n and 2 divides n.
so then 3 divides n and 2 divides n. therefore, 6 divides n.
 
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  • #9
Great! That makes 3 complete solutions for the OP to copy down. Anyone else?

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  • #10
Hello, my math skills are crap, but can't we simply do that?
If n is divisible by 6, then it can be writed as 6x where x is an integer.

[tex]\left(6x\right)^{2}=6^{2}x^{2}=36x^{2}=6\left(6x^{2}\right)[/tex]
 
  • #11
You could do that... if the intention was to show "if n is divisible by 6, then n^2 is too". But the original question was the other way around: "if true for n^2, then it's true for n".
 

1. What does it mean for a number to be divisible by 6?

When a number is divisible by 6, it means that it can be evenly divided by 6 without leaving any remainder. In other words, the number is a multiple of 6.

2. How can I determine if a number is divisible by 6?

To determine if a number is divisible by 6, you can check if the sum of its digits is also divisible by 6. Another way is to divide the number by 6 and see if the remainder is 0.

3. Are there any special rules for determining the divisibility of a number by 6?

Yes, there are a few special rules for determining the divisibility of a number by 6. For example, if the number is even (ends in 0, 2, 4, 6, or 8) and the sum of its digits is divisible by 3, then it is also divisible by 6.

4. Can a prime number be divisible by 6?

No, a prime number cannot be divisible by 6. A prime number can only be divided by 1 and itself, and 6 is not a prime number.

5. How is the divisibility of a number by 6 useful in mathematics?

The divisibility of a number by 6 is useful in various mathematical operations, such as simplifying fractions, finding common denominators, and determining factors of a given number. It is also important in number theory and can help in solving more complex mathematical problems.

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