- #1
nicktacik
- 100
- 0
This one has me stumped.
[tex]e^{\pi i} = -1[/tex]
[tex]e^{2 \pi i} = (-1) ^ 2 = 1 [/tex]
[tex]ln(e^{2 \pi i}) = ln(1) = 0 [/tex]
[tex]2 \pi i = 0 [/tex]
Or is 2 pi i actually 0, and this does not actually imply that either pi = 0 or i = 0?
[tex]e^{\pi i} = -1[/tex]
[tex]e^{2 \pi i} = (-1) ^ 2 = 1 [/tex]
[tex]ln(e^{2 \pi i}) = ln(1) = 0 [/tex]
[tex]2 \pi i = 0 [/tex]
Or is 2 pi i actually 0, and this does not actually imply that either pi = 0 or i = 0?
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