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miamirulz29
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Homework Statement
A 5.79KG block is held in equilibrium on an incline by the horizontal force F, as shown in the figure. Determine the magnitude of F. Answer in units N. The figure is in the attachment, problem 008.
Homework Equations
SigmaF=0
Fgx=mg(SinTheta)
Ffr(force of friction)= mu(fn)
Fn= Fgy
Fgy= mg(CosTheta)
The Attempt at a Solution
Through those equations, I eventually got this:
F= mg(SinTheta) - mu[mg(cosTheta)]
F= 6.052
That answer is wrong, can someone please tell me what I am doing wrong. Thanks in advance.