Related rates problem (involving a cone)

In summary, a pile of gravel is being dumped from a conveyor belt at a rate of 30 cubic feet per minute and forms a right circular cone with a base diameter and height that are always equal. The height of the pile is increasing at a rate of ____ feet per minute when the pile is 11 feet high. The volume of a right circular cone is given by (1/3)*pi*(r^2)*h, where r is the radius and h is the height. Since the problem states that the radius and height are equal, we can substitute r = 0.5h. Therefore, the height of the pile is increasing at a rate of 0 feet per minute when the pile is 11 feet high.
  • #1
Pupil
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Homework Statement


Gravel is being dumped from a conveyor belt at a rate of 30 cubic feet per minute. It forms a pile in the shape of a right circular cone whose base diameter and height are always the same. The height of the pile is increasing at a rate of ____ feet per minute when the pile is 11 feet high.

Recall that the volume of a right circular cone with height h and radius of the base r is given by (1/3)*pi*(r^2)*h.

Homework Equations


Noted above.

The Attempt at a Solution


I don't understand the problem. If the radius and the height are always the same how can they change?

EDIT: if I am thinking of this correctly then the answer would be 0 (which is incorrect).
 
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  • #2
It's saying the diameter and the radius both vary with time but are always equal at any given time. I.e. r=h. It isn't saying they are always the same in the sense that they are constant. Try and make an attempt again.
 
  • #3
Dick said:
It's saying the diameter and the radius both vary with time but are always equal at any given time. I.e. r=h. It isn't saying they are always the same in the sense that they are constant. Try and make an attempt again.

Oh! That makes things much clearer! Thanks!
 
  • #4
Dick said:
It's saying the diameter and the radius both vary with time but are always equal at any given time. I.e. r=h. It isn't saying they are always the same in the sense that they are constant. Try and make an attempt again.

Point of clarification: The problem says the diameter and HEIGHT vary with time, but they are equal to each other. So d = 2r = h, or r = 0.5h.
 

1. What is a related rates problem involving a cone?

A related rates problem involving a cone is a type of mathematical problem in which the rates of change of two or more related variables are given, and the goal is to find the rate of change of a third variable, typically the volume or surface area of a cone.

2. How do you set up a related rates problem involving a cone?

To set up a related rates problem involving a cone, you first need to identify the variables and rates of change that are involved. Then, you can use the formula for the volume or surface area of a cone, along with the given rates of change, to create an equation that relates the variables. From there, you can use implicit differentiation to solve for the desired rate of change.

3. What are some real-life applications of related rates problems involving cones?

Related rates problems involving cones have many real-life applications, such as calculating the rate at which a water tank in the shape of a cone is filling or emptying, determining the rate at which a sandpile in the shape of a cone is growing or shrinking, or finding the rate at which a cone-shaped volcano is erupting.

4. What are some common mistakes made when solving related rates problems involving cones?

One common mistake when solving related rates problems involving cones is not correctly setting up the equation that relates the variables. It is also important to carefully differentiate each term in the equation and use appropriate units for the rates of change. Additionally, forgetting to take the derivative of the constant terms can lead to incorrect solutions.

5. What are some tips for solving related rates problems involving cones?

Some tips for solving related rates problems involving cones include carefully labeling all given rates of change and variables, using a diagram to visualize the problem, and setting up the equation before taking derivatives. It is also helpful to check your final answer to ensure it makes sense in the context of the problem.

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