Deriving Helmholtz Thermodynamic Potential & Corresponding Maxwell Relation

In summary, the conversation discusses how to state the differential form of the Helmholtz thermodynamic potential and derive Maxwell's relation. The Helmholtz function and its differential form are calculated, and it is shown that F is a function of state. The condition for an exact differential is applied, resulting in the derivation of the Maxwell relation. The conversation concludes with confirmation and approval of the solution.
  • #1
Hart
169
0

Homework Statement



To state the differential form of the Helmholtz thermodynamic potential and
derive the corresponding Maxwell's relation.

Homework Equations



Stated within the solution attempt.

The Attempt at a Solution



  • Helmholtz function: [tex]F = U - TS[/tex]


  • Calculating the differential form:

    For infinitesimal change: [tex]dF = dU - tdS - SdT[/tex]

    Then using: [tex]TdS = dU + PdV[/tex] ,

    Therefore:

    [tex]dF = -PdV - SdT[/tex]


  • Which then follows that can write: [tex]F = F(V,T)[/tex]

    Hence:

    [tex]dF = \left(\frac{\partial F}{\partial V}\right)_{T}dV + \left(\frac{\partial F}{\partial T}\right)_{V}dT[/tex]


  • Comparing coefficients in the previous two stated expressions for [tex]dF[/tex]:

    [tex]P = -\left(\frac{\partial F}{\partial V}\right)_{T}[/tex]

    and

    [tex]S = -\left(\frac{\partial F}{\partial T}\right)_{V}[/tex]


  • Then as F is a function of state, then dF is an exact differential and
    the condition for an exact differential gives:


    [tex]\left(\frac{\partial P}{\partial T}\right)_{v} = \left(\frac{\partial S}{\partial V}\right)_{T}[/tex]

    Which is the Maxwell relation, derived as required.
 
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  • #2
Looks good to me.
 
  • #3
Brill.. :biggrin: .. just wanted to check it through with someone else!
 

1. What is the Helmholtz thermodynamic potential and why is it important in thermodynamics?

The Helmholtz thermodynamic potential, also known as the Helmholtz free energy, is a thermodynamic potential that represents the maximum amount of useful work that can be extracted from a thermodynamic system at constant temperature and volume. It is important in thermodynamics because it allows us to analyze and predict the behavior of a system under isothermal and isochoric conditions, which are common in many real-world applications.

2. How is the Helmholtz potential derived?

The Helmholtz potential is derived from the first and second laws of thermodynamics, and it is given by the equation F = U - TS, where U is the internal energy of the system, T is the temperature, and S is the entropy. It can also be derived using the Legendre transform of the internal energy with respect to entropy.

3. What is the corresponding Maxwell relation for the Helmholtz potential?

The corresponding Maxwell relation for the Helmholtz potential is the relation between the second derivatives of the potential with respect to temperature and volume. It is given by the equation (∂²F/∂T∂V) = - (∂²U/∂V∂S). This relation is useful in determining the behavior of a system under constant temperature and volume.

4. How can the Helmholtz potential and Maxwell relation be applied in real-world situations?

The Helmholtz potential and Maxwell relation can be applied in various fields, including chemistry, physics, and engineering. They can be used to predict the equilibrium state of a system, calculate thermodynamic properties such as heat capacity and compressibility, and analyze the behavior of complex systems such as phase transitions and chemical reactions.

5. What are the limitations of using the Helmholtz potential and Maxwell relation in thermodynamics?

The Helmholtz potential and Maxwell relation are only applicable to systems that are at constant temperature and volume. They also assume that the system is in thermodynamic equilibrium, which may not always be the case in real-world situations. Additionally, these concepts may not be applicable in systems with phase transitions or non-equilibrium processes.

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