- #1
mounith
- 3
- 0
hello everyone,
In a hydraulic cylinder high amount of load is lifted by applying lower loads in smaller diameter side..
for example, if the diameters of two cylinders is 2cm and 4 cm and i applied a force of 10 N on the 2cm cylinder for 4m downwards. so now the 4cm diameter cylinder could lift a load of 40 N through 1 m... so the work done on both the sides is balanced..
work done = force*displacement
10*4=40*1
But, what if i placed only 20 N load..
the work done on both sides is not balanced...
where does the remaining energy go..?
thanks..
In a hydraulic cylinder high amount of load is lifted by applying lower loads in smaller diameter side..
for example, if the diameters of two cylinders is 2cm and 4 cm and i applied a force of 10 N on the 2cm cylinder for 4m downwards. so now the 4cm diameter cylinder could lift a load of 40 N through 1 m... so the work done on both the sides is balanced..
work done = force*displacement
10*4=40*1
But, what if i placed only 20 N load..
the work done on both sides is not balanced...
where does the remaining energy go..?
thanks..