As a gyroscope precesses, its center off mass moves in a circle

In summary, the textbook explains that as a gyroscope precesses, its center of mass moves in a circle with radius r in a horizontal plane, and the vertical component of acceleration is zero. This means that the upward normal force exerted by the pivot must equal the weight of the gyroscope. However, in cases where the gyroscope is not precessing at the exact rate required to keep it near horizontal, the center of mass may accelerate vertically, meaning that the upward normal force may be less than the weight of the gyroscope.
  • #1
aaaa202
1,169
2
my textbook says:

"As a gyroscope precesses, its center off mass moves in a circle with radius r in a horizontal plane. Its vertical component of acceleration is zero so the upward normal force exerted by the pivot must equal mg."

Now wouldn't this always be true. I mean if u have a flywheel attached to a pivot and at first don't let it spin. Then the weight of it produces a torque that makes the arm rotate till it hits something, e.g. itself or the table it stands on. But its not translating linearly, so isn't there also a normal force exerted upwards by the pivot in this case? It just doesn't produce a torque since it's distance to the rotation axis is zero.
 
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  • #2


aaaa202 said:
Now wouldn't this always be true.
No. In your example of the non-spinning flywheel, the vertical component of acceleration would not be zero. It's falling. There would be an upward normal force at the pivot, but it wouldn't equal mg.
 
  • #3


what would it equal then? And what is it that makes the pivot exert a normal force in the case, where the flywheel IS spinning?
 
  • #4


aaaa202 said:
what would it equal then?
Something less than mg. You could figure it out by computing the acceleration of the falling flywheel.
And what is it that makes the pivot exert a normal force in the case, where the flywheel IS spinning?
The flywheel has weight.
 
  • #5


I don't get it. The flywheel isn't exactly falling it's just being rotated by the torque of its weight.
 
  • #6


aaaa202 said:
I don't get it. The flywheel isn't exactly falling it's just being rotated by the torque of its weight.
Its center of mass is accelerating downward.
 
  • #7


If the gyroscope is not precessing at the exact rate required to keep it near horizontal, it's center of mass is accelerating vertically. It could be oscillating up and down at it's rate of precession also oscillates.

If the gyroscope's center of mass isn't accelerating downwards at 1 g, then there's some force applied at the post opposing gravity. If the center of mass isn't accelerating vertically, then the upwards force from the post is m g.
 

1. What is a gyroscope?

A gyroscope is a device that consists of a spinning wheel or disk mounted on a set of axes. It is used to measure or maintain orientation and angular velocity.

2. How does a gyroscope precess?

A gyroscope precesses when a force is applied to it that is not aligned with its axis of rotation. This causes the gyroscope's center of mass to move in a circular motion.

3. Why does the center of mass move in a circle?

The center of mass moves in a circle because of the conservation of angular momentum. When a force is applied to the gyroscope, the angular momentum of the spinning wheel causes the center of mass to move in a circular motion.

4. Is the motion of the center of mass in a gyroscope always circular?

No, the motion of the center of mass in a gyroscope can also be elliptical if the applied force is not perpendicular to the spinning axis. However, in most cases, the motion is circular.

5. What is the significance of the center of mass in a gyroscope?

The center of mass in a gyroscope is important because it is the point where the weight of the gyroscope is concentrated. This is what allows the gyroscope to maintain its orientation and resist external forces.

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