- #1
maverick_starstrider
- 1,119
- 6
I'm getting myself confused here. If my relativistic Lagrangian for a particle in a central potentai is
[tex]L = \frac{-m_0 c^2}{\gamma} - V(r) [/tex]
should
[tex] \frac{d L}{d \dot{\theta}} [/tex]
not give me the angular momentum (which is conserved)? Instead I get
[tex] \frac{d L}{d \dot{\theta}} = -4 m v r^2 \dot{\theta}\gamma [/tex]
[tex]L = \frac{-m_0 c^2}{\gamma} - V(r) [/tex]
should
[tex] \frac{d L}{d \dot{\theta}} [/tex]
not give me the angular momentum (which is conserved)? Instead I get
[tex] \frac{d L}{d \dot{\theta}} = -4 m v r^2 \dot{\theta}\gamma [/tex]