- #1
synthetic.
- 12
- 0
The question as is written :
Solve for x
5cosx-2= -0.72 ( 0 [tex]\leq[/tex] x [tex]\leq[/tex] 2[tex]\Pi[/tex] )
(The answer given is "1.31, 4.97".)
So, i done what seemed natural.
5cosx-2=-0.72
5cosx = 1.28
cosx = 1.28/5
cosx = 0.256
Firstly, I'm not even sure what unit my answer is supposed to be in. Since x is defined as Radians in the question, my answer of .256 = .256pi Radians (.256 of 180)?
Which should give solutions in the 1st & 4th quadrants.
All of the questions until (there are a bunch similar to this) these ones have been in the form of, for example, 4=5 - tan2x (x in radians), which, as there are no decimals in the solution work out easy (pi/8, 5pi/8).. . why, if x is defined in Radians in the question, are the answers in decimals? I don't understand the principle of this when decimals are involved for some reasons.
Solve for x
5cosx-2= -0.72 ( 0 [tex]\leq[/tex] x [tex]\leq[/tex] 2[tex]\Pi[/tex] )
(The answer given is "1.31, 4.97".)
So, i done what seemed natural.
5cosx-2=-0.72
5cosx = 1.28
cosx = 1.28/5
cosx = 0.256
Firstly, I'm not even sure what unit my answer is supposed to be in. Since x is defined as Radians in the question, my answer of .256 = .256pi Radians (.256 of 180)?
Which should give solutions in the 1st & 4th quadrants.
All of the questions until (there are a bunch similar to this) these ones have been in the form of, for example, 4=5 - tan2x (x in radians), which, as there are no decimals in the solution work out easy (pi/8, 5pi/8).. . why, if x is defined in Radians in the question, are the answers in decimals? I don't understand the principle of this when decimals are involved for some reasons.