Pair Annihilation and Conservation of Momentum and Energy Explained

In summary, the conversation discusses the process of solving for the momentum and energy of a pair of particles through conservation of momentum and energy. The final step involves adding the two equations and solving for p1 and p2. This is a common algebraic technique and can also be applied in other situations.
  • #1
jk4
I'm a little unsure about a certain part of this shown in a book.
There is an electron and a positron moving in the +x direction. They annihilate each other and release 2 photons. to conserve momentum 1 moves in the -x and one in the +x direction.
So then the first step is to do conservation of momentum: [tex]p_{1} - p_{2}[/tex] (photon momentum 1 - photon momentum 2). It's a (-) because the second photon moves in the -x direction.

Then we find conservation of energy: [tex]p_{1}c + p_{2}c[/tex]
(obviously we set these equations equal to the electron values, but I'm leaving that out.)

Ok, so, they find values for both of those equations. But, what I'm not sure of is the next step. It says
"Now we add the two results and solve for [tex]p_{1}[/tex] and [tex]p_{2}[/tex]
so it looks like:
[tex](p_{1} - p_{2}) + (p_{1} + p_{2})[/tex]

Then I understand the rest, I just don't know why they add the 2 values. Total Energy and net Momentum.
 
Physics news on Phys.org
  • #2
jk4 said:
… conservation of momentum: [tex]p_{1} - p_{2}[/tex] (photon momentum 1 - photon momentum 2). It's a (-) because the second photon moves in the -x direction.

Then we find conservation of energy: [tex]p_{1}c + p_{2}c[/tex]

Ok, so, they find values for both of those equations. But, what I'm not sure of is the next step. It says
"Now we add the two results and solve for [tex]p_{1}[/tex] and [tex]p_{2}[/tex]
so it looks like:
[tex](p_{1} - p_{2}) + (p_{1} + p_{2})[/tex]

Then I understand the rest, I just don't know why they add the 2 values. Total Energy and net Momentum.

Hi jk4! :smile:

You have p1 + p2 = A, p1 - p2 = B.

If you add: 2p1 = A + B, and 2p2 = A - B.

So that gives you p1 and p2. :smile:

What worries you about that? :confused:

(How else would you solve it?)
 
  • #3
(How else would you solve it?)
That's why I asked. I like to learn things in a way that I don't have to do much memorizing, but so that it will be obvious to me if I ever come across it.
So I'm just not sure this will be that obvious to me.. Might have to actually consult my notes :(

Sorry, It just threw me because I'm not sure what is the significance of momentum+totalEnergy
 
  • #4
jk4 said:
That's why I asked. I like to learn things in a way that I don't have to do much memorizing, but so that it will be obvious to me if I ever come across it.
So I'm just not sure this will be that obvious to me.. Might have to actually consult my notes :(

Sorry, It just threw me because I'm not sure what is the significance of momentum+totalEnergy

Your initial question is confusing because you don't say what information was provided to you. I am assuming that they gave you the total momentum and energy of the e-e+ pair, right?


Forget about particle physics for a second. It's just algebra. Let's say you have to solve

x+y = 10

x-y = 6

How would you solve that? There is not a single way. You could isolate x from the first equation and plug in the second and then solve for y. But the quick way is of course to add them up to get rid of y.

well, this is basically exactly the same type of algebra problem you are dealing with here except that your unknowns are p1 and p2. That's all there is to it.
 

1. What is pair annihilation?

Pair annihilation is a process in which a particle and its antiparticle collide and convert their mass into energy, resulting in the production of two or more photons.

2. How does pair annihilation demonstrate conservation of momentum?

During pair annihilation, the total momentum of the particles before the collision is equal to the total momentum of the resulting photons after the collision. This demonstrates the conservation of momentum, as the total momentum of the system remains constant.

3. What is the relationship between pair annihilation and conservation of energy?

Pair annihilation is a perfect example of conservation of energy, as the total energy of the particles before the collision is equal to the total energy of the resulting photons after the collision. This is due to the principle of mass-energy equivalence, where the mass of the particles is converted into energy during the annihilation process.

4. Can pair annihilation occur spontaneously?

No, pair annihilation requires a particle and its corresponding antiparticle to come into contact and collide in order to occur.

5. How is pair annihilation used in scientific research?

Pair annihilation is used in various research fields, such as particle physics and astrophysics, to study the properties of particles and their interactions. It is also used in medical imaging techniques, such as positron emission tomography (PET), to produce images of the body's internal structures.

Similar threads

Replies
5
Views
1K
Replies
6
Views
1K
Replies
23
Views
2K
  • Advanced Physics Homework Help
Replies
10
Views
1K
Replies
7
Views
964
Replies
3
Views
2K
Replies
12
Views
735
  • Quantum Physics
Replies
2
Views
1K
  • Quantum Physics
Replies
31
Views
2K
Replies
28
Views
2K
Back
Top