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Intuitive Definition of Electric Potential |
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| Jul22-12, 08:08 AM | #1 |
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Intuitive Definition of Electric Potential
Hello all,
For a few months, I've been (off and on) trying to come up with a more intuitive definition for Electric Potential (or Voltage, if you prefer), as all I can seem to find are mathematical equations. I believe I have finally come up with a satisfactory result, and I merely wanted to verify it with those that may be more knowledgeable on this matter than I. Here's my intuitive definition: "Analogous to the electric field, which is essentially the force vector that would occur were a test charge present in the field, the electric potential (being the integral of the electric potential energy divided by a test charge) is the change in electric potential energy between two points that would occur were a test charge present in the displacement from one point to the other." This has, for me, significantly helped my intuitive understanding of it. Nevertheless, if someone finds fault with this definition in any way, please let me know, as I would hate to misinterpret the facts, especially as a undergraduate physics major! And, of course, as anyone who's taken at least a semester of physics knows, the devil's in the details. |
| Jul22-12, 11:02 AM | #2 |
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Hello Skoth!
![]() Potential energy is defined as minus the work done by a conservative force, = change in energy (by the work-energy theorem ).And electric potential energy = potential energy per charge. (an easier analogy would be to gravitational potential, which is gravitational potential energy per mass )
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| Jul22-12, 11:45 AM | #3 |
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The electric field intensity, E which is considered alwys present, whether a test charge is introduced or not. The direction of E is away from a positive charge and towards a negative one. The electric force vector, F which is the field vector multiplied by the test charge. The potential is a scalar quantity. |
| Jul22-12, 12:21 PM | #4 |
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Intuitive Definition of Electric Potential |
| Jul22-12, 12:27 PM | #5 |
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No you don't need a test charge for the electric field to be present.
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| Jul22-12, 01:09 PM | #6 |
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Yes, I know, but if a test charge were present in an electric field, then the charge would be accelerated by the field vector. The same is also true of an electric potential difference: that is, that a test charge does not need to be present for one to exist.
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| Jul22-12, 01:14 PM | #7 |
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Yes that's all correct.
Incidentally you said you didn't want to go mathematical, then mentioned integrals?
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| Jul22-12, 07:59 PM | #8 |
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Ha ha ha, good point! Well I guess all I can say to that is that the mind works in mysterious ways and mine is no different.
To quote one eminent philosopher of our generation: "The inner machinations of my mind are an enigma." --Patrick Star ![]() And thanks for the verification, guys! |
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