Trig question confusion.


by Gurdian
Tags: confusion, trig
Gurdian
Gurdian is offline
#1
Dec4-13, 03:48 PM
P: 18
Not homework just my own revision.

If sin a = –cos b = 3/5 and a and b are both in the second quadrant, what is cos (a – b)?

Now keep getting the answer 0, but the answer is apparently 24/25, now they use the trig subtraction formula, I just did cos ((arcsin(3/5) - arccos(-3/5)) I got 0 as the answer.

Was my method wrong, where did I go wrong with it?
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mathman
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#2
Dec4-13, 03:52 PM
Sci Advisor
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Both arcsin and arccos are multivalued. You need to get the possible solutions and see which are in the second quadrant.
Gurdian
Gurdian is offline
#3
Dec4-13, 03:54 PM
P: 18
Quote Quote by mathman View Post
Both arcsin and arccos are multivalued. You need to get the possible solutions and see which are in the second quadrant.
Ah that's what the explanation was talking about.


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