The electric potential difference created by point charges.

In summary: Then write an expression for the energy at some distance r from the fixed charge. Set the two expressions equal, and solve for r.In summary, to find the distance a particle with a mass of 7.20x10^-3 kg and a charge of -8.00 C travels before its speed becomes zero when fired with an initial speed of 65.0 m/s from a horizontal distance of 0.0450 m towards a fixed charge of -3.00 C, you can use conservation of energy by setting the initial total energy equal to the energy at some distance r and solving for r.
  • #1
xkelleh
1
0

Homework Statement




A charge of -3.00 C is fixed in place. From a horizontal
distance of 0.0450 m, a particle of mass 7.20x10^-3 kg and charge
-8.00 C is fired with an initial speed of 65.0 m/s directly toward the
fixed charge. How far does the particle travel before its speed is zero?



Homework Equations



My question is where do I go from KE or really how would I start this problem off?



The Attempt at a Solution



I thought that it should start off with KE so I put 1/2mv^2
 
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  • #2
You don't need kinetic energy.

First you need to find the rate of acceleration (deceleration, in this case)

Force = mass*acceleration = (charge)*electron field.

Solve for acceleration.

Then use a kinematics equation to find the time.

V(final) = V(initial)*time + 1/2 (acceleration)(time squared)
 
  • #3
Welcome to Physics Forums, xkelleh and Ifedayo.

Ifedayo said:
You don't need kinetic energy.

First you need to find the rate of acceleration (deceleration, in this case)

Force = mass*acceleration = (charge)*electron field.

Solve for acceleration.

Then use a kinematics equation to find the time.

V(final) = V(initial)*time + 1/2 (acceleration)(time squared)

The acceleration is not constant, so that won't work. Please watch how much help you give in the future, and let the OP do most of the thinking.

Conservation of energy is the key here. xkelleh, you could start by writing an expression for the initial total energy.
 

1. What is the electric potential difference created by point charges?

The electric potential difference created by point charges is a measure of the change in electric potential energy per unit charge between two points in an electric field. It is also known as voltage and is measured in volts (V).

2. How is the electric potential difference calculated?

The electric potential difference can be calculated by dividing the work done in moving a charge from one point to another in an electric field by the amount of charge moved. Mathematically, it is represented as V = W/Q, where V is the potential difference, W is the work done, and Q is the charge moved.

3. How do point charges create an electric potential difference?

Point charges create an electric potential difference by exerting an electric force on other charges in the vicinity. This force causes the charges to move and work is done in the process, resulting in a difference in electric potential energy between the points.

4. What factors affect the electric potential difference created by point charges?

The electric potential difference created by point charges is affected by the magnitude of the charges, the distance between them, and the medium in which the charges are present. Greater charges and smaller distances result in a larger potential difference, while the type of medium can affect the electric field and therefore the potential difference.

5. How is the electric potential difference related to electric potential and electric field?

The electric potential difference is directly related to electric potential and electric field. The electric potential at a point is the electric potential energy per unit charge at that point, while the electric field is the force per unit charge at that point. The potential difference is the change in potential energy per unit charge, which is equal to the work done per unit charge in an electric field, and is also equal to the product of the electric field and the distance between the points.

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