Mind blown by mechanical systems (2nd order)

In summary, the student is trying to understand why the damping force is not equal to the spring's velocity. They think that the spring's velocity might be related to the damper's velocity, but they are not sure how. The student has found a solution to the equation but they do not understand what the "vk" means.
  • #1
hihiip201
170
0

Homework Statement



B, K, M

Homework Equations



1. xs(t) -----spring ----mass-----damper-----fixed, derive DE for x of mass


given :2. F - > M -----spring-------damper ---- fixed in series, derive the DE for velocity of spring


The Attempt at a Solution




1. ma = -k(x-xs) - B(v)

But I don't understand, why aren't we taking the natural length of the spring into account?



2. no idea, I have the solution and it says that damping force is B(v(t) - vk) , but I have no idea what v has anything to do with damper, the relative velocity vb should just be vk - 0 to me but the textbook and the homework solution suggest otherwise.
 
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  • #2
Velocity relative to what? You haven't said what "vk" means.
 
  • #3
HallsofIvy said:
Do you not understand what a "damper" is? It is a way of introducing friction into the equation, so "damping" (reducing) the motion. Often it is thought of a some sort of hydraulic piston moving through water, but ordinary friction as an object moves over the floor will do. The whole point is, and I am sure that this is given in your text, that we can take the friction force to be proportional to, and in opposite direction to, the speed- the faster the object moves, the more the friction opposes the motion. The friction force is typically [itex]\alpha |v|[/itex] where [itex]\alpha[/itex] is some negative number. As long as your object is moving in one specific direction, you can remove the absolute value and put the sign into the constant.


I do believe I understand what a damper is, but if you look at my system (indicated in series). I can't see what v(t) of mass has anything to do with the damper.

since the damping force = B(relative velocity between each end)

in this case, right end is fixed, left end is the spring's velocity, so I just can't see why Damping force fb which is equal to fk in this case is not B(vk).
 
  • #4
HallsofIvy said:
Velocity relative to what? You haven't said what "vk" means.


oh gosh...maybe that's the key, my TA didn't say anything about the reference frame of the velocity, and multiple times they have displacement that have different references...


but i do believe v is the velocity of mass relative to the inertial frame of wall. and vk should be the spring velocity of the spring(right hand side of spring, left hand side of damper) relative to the inertia frame of the wall.
 
  • #5
Got it! vk is actually just v of the right side of spring - vm. so that makes sense that vm cancel out.but the reason why they used vk is because they want to replace it with the elemental equation 1/k * dfk/dt in the de to develop a 2nd order differential equation for the velocity.

thanks HallsofIvy.
 

What is a second order mechanical system?

A second order mechanical system is a dynamic system that can be described by a second order differential equation. It typically involves the motion of a mass attached to a spring or a pendulum.

How is a second order mechanical system different from a first order mechanical system?

A first order mechanical system only involves one state variable, such as position or velocity, while a second order mechanical system involves two state variables, typically position and velocity. This means that a second order system is more complex and can exhibit more complex behavior, such as oscillations and resonance.

What are some real-life examples of second order mechanical systems?

Some common examples of second order mechanical systems include a mass-spring system, a pendulum, a simple harmonic oscillator, and a vibrating guitar string.

What factors affect the behavior of a second order mechanical system?

The behavior of a second order mechanical system is affected by several factors, including the mass of the object, the spring constant, the damping coefficient, and the initial conditions (such as the initial position and velocity).

How is the concept of "mind blown" related to second order mechanical systems?

The concept of "mind blown" can be related to second order mechanical systems in terms of the complexity and surprising behavior they exhibit. The intricate relationships between the various factors involved in these systems can often lead to unexpected outcomes, which can be mind-blowing for those studying and analyzing them.

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